Image: Omar Khayyám's solution of third degree equations
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Description: Omar Khayyám's method of solving third degree equations. In order to solve the equation x^3 + 200x = 20x^2 + 2000, one considers the equation x^4 - 30x^3 + 400x^2 - 4000x + 20000 = 0, which has the same solutions, besides 10. The solutions of this equation are the x-coordinates of the intersection points of the circle x^2 - 30x +y^2 - sqrt(800)y + 400 = 0 and the hyperbola xy = sqrt(20000).
Title: Omar Khayyám's solution of third degree equations
Credit: Own work
Author: JCSantos
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License: CC BY-SA 3.0
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