Lee Graham facts for kids
Quick facts for kids Lee Graham |
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| Outfielder | |||
| Born: September 22, 1959 Summerfield, Florida |
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| debut | |||
| September 3, 1983, for the Boston Red Sox | |||
| Last appearance | |||
| October 2, 1983, for the Boston Red Sox | |||
| MLB statistics | |||
| Batting average | .000 | ||
| Home runs | 0 | ||
| Runs batted in | 1 | ||
| Teams | |||
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Lee Willard Graham, born on September 22, 1959, is a former baseball player. He played as an outfielder in Major League Baseball (MLB) for a short time. His only team was the Boston Red Sox in 1983.
Lee was 5 feet 10 inches tall and weighed 170 pounds. He was a left-handed batter and threw the ball with his left hand.
Lee Graham's Baseball Journey
Lee Graham played in five games during his time in Major League Baseball. He didn't get any hits in his six tries at bat. However, he did score two runs for his team. He also helped score one RBI, which means he helped a teammate score a run.
He played in the outfield for three of those games. An outfielder is a player who catches balls hit far into the field. Lee was very good at catching the ball, with a perfect 1.000 fielding average. This means he caught every ball that came his way.
Getting Started in Baseball
Lee Graham's journey into professional baseball began in 1977. He was still in high school at Forest High School (Florida) at the time.
The Boston Red Sox team chose him in the 26th round of the 1977 June Amateur Baseball draft. This draft is how professional teams pick young players to join their organizations. Lee was the 641st player chosen overall that year.
