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Seymour, Eau Claire County, Wisconsin facts for kids

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Seymour, Wisconsin
Town hall
Town hall
Location of Seymour in Wisconsin
Location of Seymour in Wisconsin
Location of Seymour in Eau Claire County
Location of Seymour in Eau Claire County
Country  United States
State  Wisconsin
County Eau Claire
Area
 • Total 32.2 sq mi (83.5 km2)
 • Land 31.2 sq mi (80.7 km2)
 • Water 1.1 sq mi (2.8 km2)
Elevation
912 ft (278 m)
Population
 (2000)
 • Total 2,978
 • Density 95.6/sq mi (36.9/km2)
Time zone UTC-6 (Central (CST))
 • Summer (DST) UTC-5 (CDT)
Area code(s) 715 & 534
FIPS code 55-72675
GNIS feature ID 1584127

Seymour is a town located in Eau Claire County, Wisconsin, in the United States. In the year 2000, about 2,978 people lived there. A smaller community, also called Seymour, is found in the southwestern part of the town.

About Seymour's Location

Seymour is a town in Wisconsin. It covers a total area of about 32.2 square miles (83.5 square kilometers). Most of this area, about 31.2 square miles (80.7 square kilometers), is land. The rest, about 1.1 square miles (2.8 square kilometers), is water. This means Seymour has some lakes or rivers within its borders.

Who Lives in Seymour?

Historical population
Census Pop.
1930 570
1940 1,283 125.1%
1950 1,248 −2.7%
1960 1,879 50.6%
1970 2,217 18.0%
1980 2,599 17.2%
1990 2,757 6.1%
2000 2,978 8.0%
2010 3,209 7.8%
2020 (est.) 3,352 4.5%

In 2000, there were 2,978 people living in Seymour. These people made up 1,108 households. A household is a group of people living together in one home. Most of these households, 863 of them, were families.

The town had about 95.6 people living in each square mile. There were also 1,151 housing units, which are places where people can live.

The people living in Seymour come from different backgrounds. Most residents were White. There were also smaller numbers of people who identified as Black, Native American, Asian, or Pacific Islander. Some people identified with two or more races. A small percentage of the population was of Hispanic or Latino origin.

Many households in Seymour had children under 18 living with them. About 69% of households were married couples. The average household had about 2.69 people. The average family had about 3.02 people.

The population included people of all ages. About 26.1% of the people were under 18 years old. The median age in Seymour was 39 years. This means half the people were younger than 39 and half were older.

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