Meduza Island facts for kids
 Meduza Island
Location in Antarctica
Meduza Island
Location in Antarctic Peninsula
Location of Meduza Island
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| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W |
| Archipelago | Wilhelm Archipelago |
| Area | 11.9 ha (29 acres) |
| Length | 670 m (2,200 ft) |
| Width | 434 m (1,424 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | uninhabited |
Meduza Island (Bulgarian: остров Медуза, romanized: ostrov Meduza) is the partly ice-covered island extending 670 m in southwest–northeast direction and 434 m in north–south direction in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 11.9 ha.
The feature is so named because of its shape supposedly resembling a jellyfish ('meduza' in Bulgarian), and in association with other descriptive names of islands in the area.
Location
Meduza Island is located at 65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W, which is 3.18 km southwest of Kosatka Island, 509 m west-northwest of Greblo Island, 2.33 km northwest of Rollet Island, 1.26 km east-northeast of Yastreb Island and 1.4 km southeast of Tyulen Island. British mapping in 2001.
Maps
