Tsankov Island facts for kids
 Tsankov Island
Location in Antarctica
Tsankov Island
Location in Antarctic Peninsula
Location of Tsankov Island
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| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W |
| Archipelago | Wilhelm Archipelago |
| Area | 9.48 ha (23.4 acres) |
| Length | 625 m (2,051 ft) |
| Width | 216 m (709 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | uninhabited |
Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.
The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.
Location
Tsankov Island is located at 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.
Maps
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Tsankov Island Facts for Kids. Kiddle Encyclopedia.