John Ward (Medal of Honor) facts for kids
Quick facts for kids
John Ward
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Born | 1847 or 1848 Arkansas |
Died | March 24, 1911 Texas |
Place of burial |
Seminole Indian Scout Cemetery Brackettville, Texas
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Allegiance | United States of America |
Service/ |
United States Army |
Years of service | 1870 - 1894 |
Rank | Sergeant |
Unit | Black Seminole Scouts, 24th Infantry Regiment |
Battles/wars | American Indian Wars |
Awards | Medal of Honor |
John Ward (born 1847 or 1848 – died March 24, 1911) was a brave soldier. He was a Black Seminole, which means he was part of a group of African Americans and Native Americans. John Ward served as a United States Army Indian Scout.
He received America's highest military award, the Medal of Honor. This award is given for incredible bravery. He earned it for his actions during the Indian Wars in the western United States.
John Ward's Story
John Ward lived in Mexico for about 20 years. In August 1870, he joined the US Army in Fort Duncan, Texas. He became part of a special group called the "Seminole Negro Indian Scouts."
On April 25, 1875, John Ward was a Sergeant with the Indian Scouts. They were working with the 24th Infantry Regiment near the Pecos River in Texas. During a scouting mission, John Ward and three other men faced a big challenge. They bravely charged against 25 people who were hostile.
Just one month later, on May 28, 1875, John Ward was given the Medal of Honor. This was for his amazing courage during that fight. Two other Black Seminole scouts, Pompey Factor and Isaac Payne, also received Medals of Honor for their part in the same charge.
John Ward left the army in October 1894. After his military service, he worked as a farmer for the rest of his life. He passed away when he was 62 or 63 years old. He was buried at the Seminole Indian Scout Cemetery in Brackettville, Texas.